Question 1
f(x) = −2(x − 3)² + 50 A network engineer models the number of meters of cable laid per hour, x hours into a shift, with the function above. What is the maximum value of f(x)?
- A.
−2
- B.
3
- C.
32
- D.
50
Answer: D. 50
In vertex form a(x − h)² + k with a < 0, the maximum is k = 50, reached at x = 3 (D). A is the leading coefficient, which only sets the width; B is the x-coordinate of the vertex, when the maximum occurs; C is f(0), the y-intercept.